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sqrt(x+iy) =+- (a+ib) , then sqrt(-x-iy) is equal to a. +-(ai -b) b. +_(a-ib)
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hint: \[\Large \sqrt{-x-iy}=\sqrt{-1(x+iy)}=\sqrt{-1}\sqrt{x+iy}=i\sqrt{x+iy}\] So \[\Large \sqrt{-x-iy}=i\sqrt{x+iy}\]
pls help...i can't see the full text..
which part is cut off? (sry for the long delay)
its okie...thanks for helpin.. :)
i got the answer..
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