Question

the hypotenuse of a triangle is 13 less than twice one leg. If the other leg is 20cm, find the length of the other sides of the triangle.

Answer 1

now we pythag it to calibrate for the unknowns

Answer 2

20^2 + L^2 = (2L-13)^2

Answer 3

and by other leg im assuming its not the given leg

Answer 4

400 + L^2 = 4L^2 -52L +196

0 = 3L^2 -52L -204

L = \(\cfrac{52\pm\sqrt{52^2-4(-204)(3)}}{2(3)}\) unless i seen it amis

Answer 5

that makes it a wierd number; but about 20.63 for L

Answer 6

which most likely means my brain lied to me along the way :)

Answer 7

maybe i shoulda rounded up;

21^2 + 20^2 = (2(21)-13)^2

441+400=(42-13)^2

841=(29)^2

841=841 .... that did it