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Mathematics 22 Online
OpenStudy (anonymous):

HELP! Can someone tell me how to graph this equation with the slope-intercept method? 5x + 2y = 30

OpenStudy (anonymous):

slope intercept form: y = mx + b y = -5x/2 +15 whre -5/2 is the slope.

OpenStudy (anonymous):

just give a value to x then what ever will come out when you solve it will be the value of y, and that will be your point on the graph, thake at least 3 or 4 points.

OpenStudy (anonymous):

15 is your constant so when graphing just -5x/2, you know that the origin is 0 since the b corresponds to the y intercept

OpenStudy (anonymous):

this is the graph -5x/2=y translated 15 units up

OpenStudy (anonymous):

then when applying your slope, it is rise over run so go down -5 and 2 over

OpenStudy (amistre64):

divide out the 30; drop the coeffs and simplify |dw:1316619453154:dw| the denoms are our intercepts

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