Question

Find an equation for the line passing through the points (2,4) and (7,-11)

Answer 1

m=(y2-y1)/(x2-x1)



m=(-11-4)/(7-2)



m=(-15)/(7-2)



m=(-15)/(5)



m=-3



So the slope of the line that goes through the points is m=-3



Now let's use the point slope formula:



y-y1=m(x-x1)



y-4=-3(x-2)



y-4=-3x-3(-2)



y-4=-3x+6



y=-3x+6+4



y=-3x+10



So the equation of the line that goes through the two points is y=-3x+10

Answer 2

your sure thats correct eh ??

Answer 3

what form do they want it in?

Answer 4

its for math 111 if that makes any sense

Answer 5

Well the answer is y=-3x+10


if that doesn't work, try placing the answer in standard form which is


3x + y = 10

Answer 6

thanks alot

Answer 7

sketch the graphy 3x-4y=24 label x intercpt and y intercept

Answer 8

plug in x = 0 and solve for y. This gives you one point

then plug in y = 0 and solve for x. This gives you the other point to help plot the line

Answer 9

huh

Answer 10

so plug in x = 0

3x-4y = 24

3(0)-4y=24

0-4y = 24

-4y=24

y = 24/(-4)

y = -6


So the y intercept is (0, -6), which is one point on your graph

Answer 11

whats the x intercept

Answer 12

plug in y = 0


3x-4y = 24


3x-4(0) = 24


3x - 0 = 24


3x = 24


x = 24/3


x = 8


So the x intercept is (8,0)