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t^2+10t+26=0
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Do you need the factors or the x-intercepts??
factors
i dont think its factorable, you are going to have to use the quadratic formula
in my book it jats says solve, but its under quadratic formula
Use the Quadratic Formula to get the x-intercepts so.. \[\frac{-b \pm \sqrt{b^2 -4ac}}{2a}\] a = 1 b=10 c=26 so plug in the numbers into the formula and you get \[\frac{-1 \pm \sqrt{10^2 - 4(1)(26)}}{2}\] simplify the expression in the radical and you get \[\frac{-1 \pm \sqrt{-4}}{2}\] simplify and you get \[\frac{-1 \pm 2i}{2}\] Those are the x intercepts but i forgot how you turn those into factors.. Maybe somebody else can finish
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