Question

Solving systems of linear equations using substitution.... y=x-3; x+y=5

Answer 1

use substitution to isolate one variable (already done here) and use it to solve the other

x+(x-3) = 5

x + x = 8

2x = 8

x = 4

use that to solve first half

y = 4 - 3

y = 1

Answer 2

2x - 3 = 5
x = 4
sub in isr equn,
y = 4-3 = 1

x=4, y=1

Answer 3

How did you come up with 8?

Answer 4

add three to both sides

Answer 5

you need to solve for x so you need x by itself

Answer 6

you could do this the other way around and solve for y first too, I just used x first

Answer 7

Thank you, that is very helpful

Answer 8

yw