Question

Given the function f(x)=6x^2+7x-8
Calculate the for value f(x+1)
I must be missing a step because I keep coming up with the wrong answer

Answer 1

\[6(x+1)^2+7(x+1)-8 =6(x^2 +2x+1) + 7x+7-8 = 6x^2 +12x + 6 + 7x + 7 - 8 = 6x^2 + 19x - 2\]

Answer 2

almost

Answer 3

6+7-8

Answer 4

now the coefficient next to the x is wrong

Answer 5

That's impossible

Answer 6

\[f(x)=6x^{2}+7x-8\]\[f(x+1)=6(x+1)^{2}+7(x+1)-8\]\[f(x+1)=6(x^{2}+2x+1)+7x+7-8\]\[f(x+1)=6x^{2}+12x+6+7x+7-8\]\[f(x+1)=6x^{2}+19x+5\]

Answer 7

That's what I had. Darn it

Answer 8

Zarkon your interference made it worse, lol

Answer 9

Hey... I was already writing that when you came. I was only slow and laggy here.

Answer 10

;)...sorry