Given the function f(x)=6x^2+7x-8
Calculate the for value f(x+1)
I must be missing a step because I keep coming up with the wrong answer

Question

hero · Answer

$$6(x+1)^2+7(x+1)-8 =6(x^2 +2x+1) + 7x+7-8 = 6x^2 +12x + 6 + 7x + 7 - 8 = 6x^2 + 19x - 2$$

zarkon · Answer

almost

zarkon · Answer

6+7-8

zarkon · Answer

now the coefficient next to the x is wrong

hero · Answer

That's impossible

anonymous · Answer

$$f(x)=6x^{2}+7x-8$$$$f(x+1)=6(x+1)^{2}+7(x+1)-8$$$$f(x+1)=6(x^{2}+2x+1)+7x+7-8$$$$f(x+1)=6x^{2}+12x+6+7x+7-8$$$$f(x+1)=6x^{2}+19x+5$$

hero · Answer

That's what I had. Darn it

hero · Answer

Zarkon your interference made it worse, lol

anonymous · Answer

Hey... I was already writing that when you came. I was only slow and laggy here.

zarkon · Answer

;)...sorry