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Mathematics 12 Online
OpenStudy (dboyette):

these always confuse me. Rank the following data in increasing order and find the positions and values of both the 43rd percentile and 67th. 0,6,3,5,2,8,1,5,2,3,8 Show all work

OpenStudy (amistre64):

how many data point we got?

OpenStudy (anonymous):

11

OpenStudy (amistre64):

then 11(.67) = ? and 11(.43) = ?

OpenStudy (anonymous):

yes - think so

OpenStudy (amistre64):

11(.67) = 7.37; P(67) is the 8th term 11(.43) = 4.73; P(43) is the 5th term

OpenStudy (anonymous):

i'm a bit hazy about these i must admit

OpenStudy (amistre64):

i aint, i got a mind like a steel seive

OpenStudy (anonymous):

i guess so - seems to make sense

OpenStudy (anonymous):

lol

OpenStudy (amistre64):

the P(50) = 11(.5); 5.5 term in the 6th spot

OpenStudy (amistre64):

if you get an integer value; you take the average of the that and the next one up from it

OpenStudy (anonymous):

right

OpenStudy (dboyette):

11(.67) = ? and 11(.43) = ? I don't get this

OpenStudy (amistre64):

you only have 11 spots total; the percentile points to the percentage placement; the term in the 67% spot

OpenStudy (amistre64):

the term in the 43% spot

OpenStudy (amistre64):

67% of 11 = 7.37; so at most, the 8th spot

OpenStudy (dboyette):

Ok now i follow from the (p) 67 = is the 8th term, but where did the (p)50 come from?

OpenStudy (amistre64):

i used that to compare the method; the p(50) is the median of the set; the number in the middle. 50% of 11 = 5.5; so the 6th term is the median, is the p(50)

OpenStudy (amistre64):

make sure you align your terms small to big tho

OpenStudy (dboyette):

ok so I put them in ascending order and the number that is sitting it the 8th place is the one for the 67th percentile?

OpenStudy (amistre64):

yep

OpenStudy (amistre64):

if there was a spot for a 7.37; then that would be it, but to include the 67th percentile we got to step it up a notch to 8

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