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2^(2x+3)=2^(x+1)+3
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\[2^{2x+3}=2^{x+1}+3\]
you there?
yeah, can you help me?
ok, this is actually a quadratic equation
the first term can be rewritten as 2(2^(x+1))^2
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when you are done solving the quadratic you will get an extraneous solution of -1/2
but you will be able to solve it for u = 3/2
could you help me with that first step
2^(2x+3) = 2* (2^(2x+2))
I just took out one of the 2s
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then you can factor out the 2 in the power to make it look like a 2^((2*(x+1))
I see! I got it now. Thank you very much.
you are welcome
could you tell me the final answer?
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