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Mathematics 20 Online
OpenStudy (anonymous):

how would i go about solving this?: x^2 = 1.3y^2 + 2

OpenStudy (anonymous):

there is one equation and two variables... for what do you want to solve? y(x) or x(y) ?

OpenStudy (anonymous):

either

OpenStudy (anonymous):

well.. first of all, it's a hyperbolic function.. and about solving it...\[y = \pm 0.877058 \sqrt{x^{2}-2}\] for example.. you just take the sqare root of both sides.. nothing else to do..

OpenStudy (anonymous):

ok thanks :)

OpenStudy (anonymous):

you're welcome :)

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