Question

Find the area of the region that lies inside the first curve and outside the second curve:
r = 2 + sin(x) and r = 3sin(x)

Answer 1

I tried this out, when i graphed it the only intersection point was at x = pi/2, so i was wondering if i just integrate from -pi/2 to pi/2 for the outside curve, get the area, then integrate from 0 to pi/2 for the second curve, get the area, take the difference, and multiply by 2? I tried doing the integral all in one go from 0 to 2pi, but i ended up with 0, why didnt that work?