Question

Solve for (x+5)^2=12

Answer 1

x=-5+or- 2 radical 3

Answer 2

Suppose
\[y^2 = 12\]
What would say is the solution or are the solutions for y?

Answer 3

if only we had a sqrt(12) in there but that +5 is getting in the way .... i say we put a hit out on it :)

-5 +- sqrt(12)

Answer 4

could it be -5-2√6,-5+2√6

Answer 5

almost; but no

Answer 6

2sqrt(6) = sqrt(24)

Answer 7

-5-2√3,-5+2√3

Answer 8

\[\sqrt{12} = \sqrt{4 \times 3} = \sqrt{2^2 \times 3} = \sqrt{2^2} \times \sqrt{3} = 2 \sqrt{3}\]

Answer 9

-2√3 2√3 has to be close

Answer 10

No, you were right above\[x = -5 \pm 2 \sqrt{3}\]