Question

1 over 5 (x + 3) = 1 over 6 (x + 7)

Answer 1

\[1/5(x+3) = 1/6(x+7) or 1/[5(x+3)] = 1/[6(x+7)] ?\]

Answer 2

1/5(x+3)=1/6(x+7)

Answer 3

'k
multiply through by 30:
30*1/5(x+3)=30*1/6(x+7)
6(x+3) = 5(x+7)
then distribute and solve

Answer 4

\[\frac{1}{5 (3+x)}=\frac{1}{6 (7+x)}\]Move the RHS to the LHS, combine fractions, set the Numerator to zero and solve for x.\[\frac{27+x}{30 (3+x) (7+x)} \]\[\frac{27+x}{30 (3+x) (7+x)}=0 \]27x=0
x = -27

Answer 5

6x+18 = 5x + 35

Answer 6

mistake, 27 + x = 0.

Answer 7

x = 35 - 18, whatever that is...

Answer 8

according to the answer key, x = 17

Answer 9

x = 17 is the solution to the following:\[\frac{x+3}{5}=\frac{x+7}{6} \]I interpreted the problem equation as follows:\[\frac{1}{5 (x+3)}=\frac{1}{6 (x+7)} \]