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Mathematics 11 Online
OpenStudy (anonymous):

grouping factor x^3+5x^2+8x+40

jimthompson5910 (jim_thompson5910):

x^3+5x^2+8x+40 (x^3+5x^2)+(8x+40) x^2(x+5)+8(x+5) (x^2+8)(x+5) So x^3+5x^2+8x+40=(x^2+8)(x+5)

OpenStudy (anonymous):

so you dont have to find a common factor?

OpenStudy (anonymous):

oh wait nevermind 5 times 8 is 40

jimthompson5910 (jim_thompson5910):

nope just factor by grouping

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