Solve the following system of equations algebraically:? Y=400+20X, Y=600+10X
well y=y so you can just set them = to each other 400+20x=600+10x solve for x
Each of these equations represents lines on a graph, the "solution" is the point where the two lines cross, thus to solve, you set the equations as equal to one another.
You can check your answer with a graphing calculator
I NEED HELP WITH THE STEPS.
well.. 400+20x=600+10x -200=10x ... finish solving for x then plug into one of the equations for y
-20x+y=400 -10x+y=600 We can use elimination for this. Multiply 2nd equation by -2 and then add together to get rid of x. -20x+y=400 20x-2y=-1200 =>-y=-800 y=800 Then plug in y and solve for x. -20x+800=400 =>-20x=-400 x=20 Try it in the other equation. -10x+400=600 -10x=-200 x=20 Hope this helps. Thanks, Sean Walsh Facebook: Tutor Sean http://www.tutorsean.net
WHERE DID YOU GET THE -20 AND THE -10 IN THE EQUATIONS? IT'S A POSITIVE 10 AND 20?
Using algebra to manipulate across the equals sign. Y=400+20X is the same as Y-20X=400+20X-20X. :)
Did that help clarify? You can use the gaussian elimination method as shown above to solve these types of equations and it makes it really easy. This is a method which is taught in some algebra classes but mainly in Linear Algebra, which shows numerous techniques. If you check out my site, there are a few free videos on linear algebra shortcuts you may find useful for systems of equations. http://www.tutorsean.net
algebraically determines when the two savings plans yield identical balances and accurately states the balance. ...using the two equation this is what i need to find....Solve the system of equations algebraically to determine when the two savings plans yield identical balances and state this balance.
You will find the same answer this way. Here is what I think you are talking about. 400+20x=600+10x 20x=200+10x 10x=200 x=20 Now plug in for x in either equation to find y.
confused...so i could just plug in any #?
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