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One solution of a quadratic equation with real coefficients is m-i√(n), find the equation
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m^2 + n
could you explain?
multiply the factor with its conjugate which is m+i sqrt(n)
would that work for all complex numbers?
Yes and with radicals I believe
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okay, maybe but what if the solution is (2-3i) then the quadratic it came from wouldn't be 13
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