I need help on a problem that I've gone to three different tutors and none of them know how to solve it. Suppose a stone is thrown at an angle of 39 degrees below the horizontal from a building that is 43 m tall. If it strikes the ground 45.4 m away, find the following. The time of flight, the initial speed, the speed and angle of the velocity vector with respect to the horizontal at impact.

Question

anonymous · Answer

My guess is starting with v_y^2=(v_0sin(Theta))^2-2g(y-y_0) since we know that the final velocity is going to be zero

stormfire1 · Answer

This will probably help...same problem with different initial values: http://answers.yahoo.com/question/index?qid=20080927111537AAdcnDe