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Differentiate function r(t)= 5t^(-3/5)
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wouldn't that be -3/t^8/5?
Im pretty sure
off by a minus sign in your exponent
should be \[-3t^{-\frac{8}{5}}\]
so its not -3 divided by t^-8/5?
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it is actually. d/dx 5x^(-3/5) = (-3/5)(5)=-3^-8/5
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