Consider all of the positive integers with exactly 5 digits(note, this means the first digit is not zero.) how many of them are even and have all 5 digits distinct?

Question

anonymous · Answer

There should be 90,000 of them.
45,000 of them should be even, and as far as how many have all 5 digits distinct, give me a moment. haha

anonymous · Answer

The number of 5 digit numbers you can make with distinct digits will be (10*9*8*7*6*5)-(9*8*7*6)  (whatever that is).

My guess is that half of them are even, but i dont know for sure >.<

anonymous · Answer

oops, mistake, its (10*9*8*7*6)-(9*8*7*6)