Question

differentiate 5x^3 + 3x^2y + 4y^3

Answer 1

d/dx(5 x^3+3 x^2 y+4 y^3)
Differentiate the sum term by term and factor out constants:
= 5 (d/dx(x^3))+3 y (d/dx(x^2))+4 (d/dx(y^3))
The derivative of x^2 is 2 x:
= 5 (d/dx(x^3))+4 (d/dx(y^3))+3 (2 x) y
The derivative of x^3 is 3 x^2:
= 4 (d/dx(y^3))+5 (3 x^2)+6 x y
The derivative of y^3 is zero:
= 15 x^2+6 x y+4 0

Answer 2

thanks.

Answer 3

np, in return give me a "Good Answer"...;P