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Solve and show steps (x-2)^-1/2=1/3 ? ^ =To the power of..
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1/((x-2)^0.5) = 1/3 square both sides 1/(x-2) = 1/9 9 = x-2 x = 11
1/sqrt(x-2) =1/3 3=sqrt(x-2) square both sides 9=x-2 x=11
where did the one in front of the problem come from?
whenever you have negative power like a^-n you can do 1/a^n so (x-2)^(-1/2) -> 1/((x-2)^(1/2))
what do you square both sides with? 1/2?
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no with 2
Ok, so when you square .5 it becomes a one, and 1/3 becomes 1/9?
nvm that last question.. but what happened to the .5
when you square it , it becomes 1 (a^(0.5))^2 = a
Im sorry, im having a difficult time understanding that part, so your squaring .5 it becomes one correct? but how when you square .5 its .25
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