I am looking for the answer of :

Write the standard form of the equation of the line passing through the point (-3, 5) and perpendicular to the line -4x -3y = -6

Question

I am looking for the answer of :

Write the standard form of the equation of the line passing through the point (-3, 5) and perpendicular to the line -4x -3y = -6

amistre64 · Answer

looking for it?  where did you last leave it?

anonymous · Answer

I pretty much got an answer but i need to know if it is right.

amistre64 · Answer

type it up and all compare

anonymous · Answer

Does it have a slope of 3/4?

amistre64 · Answer

I got mine written :)

anonymous · Answer

I have mine hidden under my hand so no one peeks :P

anonymous · Answer

:(... 

 The answer i got was -4x + 3y = 27.

anonymous · Answer

hmmmm.... I ended up with -3x+4y=29

amistre64 · Answer

-3x+4y = C
-3     5
-----------
9 + 20 = 29

-3x +4y = 29; or better yet

3x -4y = -29

amistre64 · Answer

given ax + by = c

slope = -a/b; so perp slope is b/a

in other words; swap coeffs and flip a sign

amistre64 · Answer

then calibrate the constant with the given point