Question

Write the quadratic equation given: Vertex (-2, -8) and a point: (1, 3)

Answer 1

vertex is (-2,-8) you know it looks like
\[y=a(x+2)^2-8\]

Answer 2

you just don't know a, but you know if
\[x=1\] then
\[y=3\] so solve
\[3=a(1+2)^2-8\] for a

Answer 3

i get
\[3=9a-8\]
\[11=9a\]
\[a=\frac{11}{9}\] hmm

Answer 4

ok fine it is
\[y=\frac{11}{9}(x+2)^2-8\]

Answer 5

Weird... I got a=0 lol

Answer 6

ohhh cuz i had it as y=a(x-x) alright thanks!