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5(3+x)^2 -3(3+x)+10
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This can be written out as 5(3+x)(3+x)-3(3+x)+10
(3+x)(3+x) = 9+6x+x^2 using the foil (first, outside, inside, last) method.
Simplify: \[5x ^{2} + 27x + 46\]
5(3+x)^2 - 3(3+x) + 10 5(3+x)(3+x) -9-3x + 10 5(9 + 6x + x^2) - 9 - 3x + 10 45 + 30x + 5x^2 - 9 - 3x + 10 Group some terms... 45 - 9 + 10 + 30x - 3x + 5x^2 46 + 27x + 5x^2 use the quadratic formula: \[(-b \pm \sqrt{b^2 - 4ac} ) / 2\] You can solve. a = 5, b = 27, c = 46
You can solve, but you wont get a real answer, since the square root will be of a negative number.
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thanks everyone!
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