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OpenStudy (anonymous):
Prove: Suppose that P(AnBnC) = P(A)P(B)P(C), P(A^cnBnC) = P(A^c)P(B)P(C), P(AnB^cnC) = P(A)P(B^c)P(C), P(AnBnC^c) = P(A)P(B)P(C^c) Suppose A, B, and C are independent. Then so are A^c, B, and C. n = intersection ^c = complement
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