Question

Solve 3x^3 - 4x^2 - 12x + 16 = 0

Answer 1

we can write:
(3x^3 - 12x) + (-4x^2 +16) = 0
3x^2(x-4)-4x(x-4)=0

Answer 2

What are you wanting to do exactly?

Answer 3

There are several ways to answer this equation

Answer 4

(3x^3 - 12x) + (-4x^2 +16) = 0
3x^2(x-4)-4x(x-4)=0
(x-4)(3x^2-4x) = 0
x(3x-4)(x-4) = 0

x = 0, 4/3, 4

Answer 5

thanks. I forgot minus symbol

Answer 6

I copied what you already wrote and just finished it