Question

elimination method 4x+y=-4 6x+y=-10

Answer 1

y = -4 -4x

plug it into 6x+y=-10

6x -4 -4x = -10
2x = -6
x = -3
return to y = -4 -4x
and get : y = -4 + 12 = 8

(-3,8)

Answer 2

that is the substitution method

Answer 3

Solve for one, either X or Y, then plug into the other equation.

So if we solve for y in the first equation, we have

4x+y=-4
or
y = -4 - 4x

Now we can plug -4 + 4x in eveywhere we see Y in the second equation

We have

6x+y=-10
6x + (-4 - 4x) = -10

This gives us 6x -4 - 4x = -10
Which is

2x -4 = -10
2x = -6
x = -3

And we can take this x and plug it back into our answer for y, which was

y = -4 - 4x

giving us

y = -4 - 4(-3)

so we have

y = -4 +12
and so
y=8

So we have
x=-3, and y=8

Answer 4

oh elimination so :
4x+y=-4
6x+y=-10

subtract the second from the first to get :

-2x = 6
x= -3
then plug it into the first

-12 +y = -4
y = 8

Answer 5

to eliminate, say, the y-variables, mutliply the first equation by -1 and then form a linear combination of the two:

-4x - y = 4
6x + y =-10
=========
2x =-6
x=-3

now you can sub x=-3 into any eqaution above that has a y-variable in it; i choose the second given eqation:

6(-3) + y = -10
y=-10+18
y=8

the solution is x=-3; y=-8; or as an ordered pair (-3, 8)