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integrate ln5^x
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is it (ln5)^x
or ln[ (5^x)]
no it is ln(5^x)
if it is second case then it's easy.
bring the x down in front by the log rule.
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is it 1/x *1/5^X ?
\[= \int\limits x \ln(5) dx= \ln(5) \int\limits x dx = \frac{\ln(5)}{2} x^2 +C\]
ln(5) is a constant.
answer in the book is x(log5^x)-1/2 (x^2)log5+C
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