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OpenStudy (anonymous):
(6z-u)(2z+3u)
i got 12 to the 2nd power am i on the right track here ?
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OpenStudy (anonymous):
u want to multiply the two factors to get a single one?
OpenStudy (anonymous):
12z^2 is your first number
OpenStudy (anonymous):
12z^2+16uz-3u^2
OpenStudy (anonymous):
how did you get the second part from, see that is where im lost at and the foil thing just makes me even more lost
OpenStudy (anonymous):
-u *2z + 3u*6z
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OpenStudy (anonymous):
18uz-2uz=16uz
OpenStudy (anonymous):
how about this problem (7z-u)(5z+2u)
i get 35z to the second power am i right so far
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so then the secon part would 2u to the second power right
OpenStudy (anonymous):
-2u^2
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OpenStudy (anonymous):
lost i get the first part and the last part which would be 2u to the 2nd power right?
OpenStudy (anonymous):
the first u is negative. you forgot to bring it with you. now you gotta do the uz's
OpenStudy (anonymous):
so that would now be 35z to the 2nd power - 2u to the 2nd power then the last part would 2uz to the 2nd power right?
OpenStudy (anonymous):
no. -5uz+14uz=9uz
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