Question

Use the Laws of logarithms to rewrite the expression log2(2x(x−16))
in a form with no logarithm of a product, quotient or power.
After rewriting we will have: log2(2x(x−16))=log2^A+log2x+log2f(x)

what is the constant (A)

what is the function f(x)

Answer 1

\[\log_{2}(2x(x-16))\]¿Es esto con lo que necesitais ayuda?

Answer 2

necesito A and B

Answer 3

So you want me to re-write that thing as follows:\[\log_{2}(A)+\log_{2}(2x)+\log_{2}(f(x))?\]

Answer 4

\[\Large \log_{2}\left(2x(x-16) \right)\]


\[\Large \log_{2}\left( 2\right) + \log_{2}\left( x\right) + \log_{2}\left( x-16\right)\]


So A = 2 and f(x) = x-16