Question

What is the limit of ( x^2 - 1/x) as x approaches 0 from negative infinite ?

Answer 1

\[\lim_{x\to 0^{-}}\frac{x^2-1}{x}\]

Answer 2

yeah that

Answer 3

\[\infty\]

Answer 4

how?

Answer 5

\[x \to 0^{-} \implies \frac{1}{x} \to -\infty\]

Answer 6

x is negative. hence, less than 1 making \((x^2 -1 )\) negative

Answer 7

thanx