Question

the perimeter of a rectangle is 146 m. The length is 1 m more than twice the width. Find the dimensions

Answer 1

Suppose the width be x.

So the length be: 1+2x.

Now, substitue them into the formula.

Perimeter = 2(Length + Width)
146 = 2( (1+2x) + x))

Now solve for x to get the width.

Answer 2

how do i solve for x

Answer 3

146 = 2( (1+2x) + x))

Answer 4

146 = 2(2+3x)

Now.

Answer 5

This is how I work problems out:

"the perimeter of a rectangle..."

I read perimeter, thus it must have something to do with:\[P=2(l+w),\]where l and w are the length and width, respectively.

"... is 146 m..."

Then I know my formula should be modified to:\[146=2(l+w).\]

"... The length is 1 m more than twice the width...."

That said, I know that\[l=2w+1.\]

"... Find the dimensions."

Hmm, I think I need to solve the following system:\[146=2(l+w)\]\[l=2w+1\]Can you do that?