Question

please help! I forgot how to do this stuff.
Solve the compound inequality 6b < 42 or 4b + 12 > 8.

b < 6 or b > 5

b < 7 or b > −1

b < 7 or b > 1

b > 6 or b < 5

Answer 1

solve separately
\[6b<42\]
\[b<42\div 6\]
\[b<7\]OR
\[4b+12>8\]
\[4b>-4\]
\[b>-1\]

Answer 2

so your answer according to your choices is
\[b<7\] or
\[b>-1\] but in fact your actual answer should be b can be any number, because all numbers are less than 7 or greater than -1

Answer 3

oh okay! That was eassyy. Sorry for wasting your time with a stupid problem haha. thanks!!

Answer 4

where exactly did this question come form because no one on planet earth says "b is less than seven or b is greater than minus one" since all numbers fit this bill

Answer 5

no problem
doing the work is not stupid, but the answer given certainly is

Answer 6

a example problem in my online math thing

Answer 7

figures

Answer 8

< <---- can be viwed as = signs. 6b< 42 divide... anser is 7! :))

Answer 9

Answer*