I don't get what it mean by ''real numbers a and b''

solve the following equation for the real numbers a and b.

((1+i)/(1-i))^2+(1/(a+ib))=1+i

Question

I don't get what it mean by ''real numbers a and b''

solve the following equation for the real numbers a and b.

((1+i)/(1-i))^2+(1/(a+ib))=1+i

amistre64 · Answer

thats because you are a victim of bad naming ...

amistre64 · Answer

real numbers are numbers found on the real number line ...

anonymous · Answer

Complex numbers come in the form a+bi so they want you to simplify the expression to the form a+bi

anonymous · Answer

so they just want to simplify it right?

anonymous · Answer

yep

anonymous · Answer

it is just saying solve for a and b but since you are working with complex numbers they are specifying that a and b are real numbers and not say 
$$a=x+iy$$ for example

anonymous · Answer

they could have written 
$$(\frac{1-i}{1+i})^2+\frac{1}{z}=1+i$$ solve for z