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if f(2)=3 and f'(2)=5 find and equation of the tangent line and the normal line to the graph of y=f(x)
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you have the point and the slope, so use the point - slope formula \[y-y_1=m(x-x_1)\] with \[m=5, x_1=2,y_1=3\]
how do you know that the slope is 5?
because the derivative is the slope of the tangent like. or rather the derivative gives the slope of the tangent line
you are told \[f'(2)=5\] which means at \[(2,3)\] the slope of the tangent line is 5
okay thanks a lot what is the difference between f(x) and f'(x)?
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. . . f'(x) is the derivative of f(x) . . . By asking that you basically just told Satellite that you weren't listening to a word he was saying when he was wasting his time trying to explain the problem to you. -_-'
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