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Find the slope of the following curve at x=5 y= 1/(x-2) No idea how to do really.explaination needed
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slope is the value of first derivative at the indicated point
I thought that..just no idea how to find here. havent done it yet
do u know how to find the derivative of a function?
y=(x-2)^(-1) y'=(-1)(x-2)^(-2) just put x=5 to find slope
What? we were told to do like. F(xo+h)-F(x)/h
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yea right, but that is by definition.here i used power rule to find the derivative
if y=x^n y'=nx^(n-1)
No idea how that works..but i guess it does. Thanks Ill have to ask professor. I dont get how you got the y1=(-1)(x-2)^(-2)
ok, i mentioned the power rule that i used,
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