Question

How do I graph the following using a graphing calculator: (x+1) ^2 + (y-2)^2=9

Answer 1

if you need y = something

(y-2)^2 = 9 -(x+1)^2
(y-2) = +/-sqrt(9 - (x+1)^2)
y = +/-sqrt(9-(x+1)^2) + 2

Answer 2

I got that too. What would the graph look like? Having a hard time with my calculator.

Answer 3

circle

Answer 4

centered at -1,2 radius 3

Answer 5

I know it's a circle but I'm not getting one on my calculator.

Answer 6

\[y = 2 +/-\sqrt(9-(x+1)^2)\]

Answer 7

the square root is above -(x+1)^2 as well

Answer 8

this is what i get when i type in all that info in my calc... is that what u get too?

Answer 9

let x be negative as well .. the circle should look like :

Answer 10

let x be between -10 ,10
and y between -10,10 as well

Answer 11

why dont i get the whole circle?

Answer 12

it's two graphs .. one positive and one negative

Answer 13

i put in both but it only shows me the positive side

Answer 14

what is the range of values for your x and y ?

Answer 15

i dont know what that is? are you talking about "window" because i dont know how that works

Answer 16

*that is.

Answer 17

yes the window ..

Answer 18

i dont know what to put in there and how i know what to put in

Answer 19

:(