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-12a^6+8a^5-4a^4 inst difference of cube
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try factoring out an a^4.
i dont know how
We know that all terms in the equation contain the term a^4, so can we pull that out of the equation?
so if i do 4a^3(-12a^6+8a^5-4a^4)
so its 3a^3+2a^2-a
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exactly, but recall that when we factor out terms, they don't disappear from the equation, they just become coefficients. Also, every term has an a in it, so can we still factor out another "a"?
ok so 3a^2+2^a
when we factor, an "a" from a "-a" does it become 0?
it did
Unfortunately it does not! Whenever we factor an "a" from a "-a" the "-a" then becomes a -1. Thus our equation would look more like: (4a^4)(-3a^2+2a-1) Yes? (I would also pull out a negative to make things simpler)
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