Question

If 2^x=3, whats 4^-x=?

Answer 1

2^x = 3
4^-x = 2^(-2x) = 3^-2 = 1/9

Answer 2

wait how does 4^-x= 2^(-2x)?
and where do the 2 and x when you get to 3^-2?

Answer 3

4^-x = 2^-2x because 4 = 2^2 so if you manipulate, 4^-x = 2^2(-x) correct?

so 4^-x = 2^-2x

now i got 3^-2 from the previous equation
2^x = 3
so when 2^-2x, for both sides to be equal, you must also raise the other side by -2 so i got 3^-2. Did that answer your question?

Answer 4

yeah thanks