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factor the trinomial completely. 2x^2+32x-34
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make your live easier by starting with \[2(x^2+16x-17)\]
ok that's what i'm trying to figure out thanks
you mean you are trying to figure out \[x^2+16x-17\]? two numbers whose product is -17 and whose sum is +16 since 17 is prime you don't have too many choices
(2x-2)(x+17)
in other words \[2(x-1)(x+17)\]
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ah okay thanks
so would 3x^2y+15xy-6y be 3x^2y+5xy-3y?
no
each term has a common factor of 3y. factor that out first
in other words write \[3y(\text{ something })\]
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that's what I am trying to figure out
3y(x^2+5x-3)?
3y(x^2+5x-2)
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