Question

bc+3g=2k, for c

Answer 1

Are you supposed to be solving for c?

Answer 2

bc = 2k - 3g

\[c = \frac{2k - 3g}{b}\]

Answer 3

thanks

Answer 4

how did you get that?

Answer 5

First you subtract 3g from both sides of the equation to give you:
\[bc + 3g - 3g = 2k - 3g\]

Answer 6

The 3g's cancel out on the left side of the equation, leaving you with:
\[bc = 2k - 3g\]

Answer 7

Next you divide both sides of the equation by b to give you:
\[\frac{bc}{b} = \frac{2k-3g}{b}\]

Answer 8

Once again, b/b = 1, so the b's cancel out on the left side of the equation. This leaves you with:
\[c=\frac{2k−3g}{b}\]

Answer 9

Clear as mud?