Find the value of x so that the line passing through the points will have the given slope: (x, 6) and (10, -3) with a slope of -3/2

Question

agreene · Answer

your slope is the change in y over the change in x or 
$$\Delta y/\Delta x$$ 
so, with these two points, we plug in and solve for x
-3/2 = (-3-6)/(10-x)
-3/2 = -9/(10-x)                  multiply both sides by the denominator
(10-x)*-3/2 = -9            divide by -3/2
10-x = -9/(-3/2)   
10-x=6                          subtract over your 10
-x= -4                           multiply both sides by -1
x=4


:)