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Mathematics
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OpenStudy (anonymous):
Which following relation is NOT a function?
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OpenStudy (anonymous):
OpenStudy (anonymous):
the last one
OpenStudy (anonymous):
ok can u tell me why
OpenStudy (anonymous):
yes, what this really means is "is y a function of x"
OpenStudy (amistre64):
..becasue it doesnt fit the definition of a function :)
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OpenStudy (anonymous):
So what is the definition smart one
OpenStudy (amistre64):
something that should be known in order to answer the questions id assume ;)
OpenStudy (anonymous):
so what happens if you solve for y? you get
\[y^2=x^2-4\]
\[y=\pm\sqrt{x^2-4}\]
and it is the plus or minus that throws you off
OpenStudy (amistre64):
if you try to solve this with a table; the points that you come up with will not be "unique" enough
OpenStudy (anonymous):
Thanks you satellite :-)
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OpenStudy (amistre64):
they will give you 2 results for every entery
OpenStudy (anonymous):
so for example if x = 5 then y could be 1 or -1
OpenStudy (anonymous):
Do you think you can help me with a couple more?
OpenStudy (anonymous):
hello amstre! i have been busy all day
OpenStudy (amistre64):
ive been doing homework for the first part, now i got time to just be bored
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OpenStudy (anonymous):
@jessica post away!
OpenStudy (anonymous):
thanks!
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