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implicit differentiation y = sin(7xy) show steps please
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\[y'=7\cos(7xy)\times(y+xy')\] is a start
only not obvious part is that the derivative of \[xy\] requires the product rule, since you are thinking of y as a function of x. like taking the derivative of \[xf(x)\] using the product rule. you would get \[(xf(x))'=f(x)+xf'(x)\] but here you write \[y+xy'\]
then algebra to solve for \[y'\]
whats is wrong with this site, i am trying to post and answer and it freezes on me and then i have to refresh and i lose everthing i wrote
very very slow tonight
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yeah its been slow for a couple of nights now
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