how do i solve this bernoulli differential equation??
y' + xy = 6xy^(1/2)

i got to the part where you find the linear equation and i got.. z' = 3x + x/2y

but I dont know who to solve that equation.

Question

how do i solve this bernoulli differential equation??
y' + xy = 6xy^(1/2)

i got to the part where you find the linear equation and i got.. z' = 3x + x/2y

but I dont know who to solve that equation.

anonymous · Answer

Google :)

amistre64 · Answer

tell bernoulli to do his own work or else hell never learn :)

jamesj · Answer

Divide your original equation by y^(1/2) and you have

y'/y^(1/2) + x y^(1/2) = ....

Now set u = y^(1/2)
then u' = (1/2) y'/y^(1/2)

Substitute for y and y' in the equation above and now you should be able to solve the equation for u.

jamesj · Answer

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