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(3,-3),y=x+5 Write an equation of the line that passes through the given point and is perpendicular to the given line.
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x=y
dont you have to make the given slope opposite
sorry x=-y
sritama idont think thats right
why not -x
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perpendicular means if the first line's gradient is n, the other line's gradient is -1/n so the line you are looking for has the gradient of -1/1 which is just -1 (y-(-3))/(x-3)=-1 y+3=-x+3 y=-x+6
oops y+3=-x+3 y=-x silly mistake, sorry
hmmmm
|dw:1317976174533:dw| Draw the picture. It all becomes clear.
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