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\[8^(8 - x^2)\]
8 raised to the power of (8 - x^2).. its kinda hard to tell
Multiply the 8 through and you get 64 - 8x^2= -16x
oh wait 8^(8-x^2)? Nevermind hang on.
nono.. its 8^(8 - x^2)
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First rewrite it as 8^8 * 8^-(x^2). 8^8 is just a constant, so it stays out front. then we have chain rule of a power to the x. d(a^x)/dx = ln(a)a^x So, we get 8^8 * ln(8) * 8 ^ -(x^2) * (-2x)
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