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solve ⎷‾13x+13‾ = x+1 (13x+13 is under a factor sign)
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what, you mean a radical sign? \[\sqrt{13x+13}=x+1\]
yes thats it!
you want to solve for x?
yes. its X= either 1 or 2 answers
sure, square both sides to get rid of the sign 13x+13=(x+1)^2=(x+1)(x+1)=x^2+2x+1 combine like terms and set equal to zero: x^2-11x-12=0 (x-12)(x+1)=0 x={-1,12}
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follow all that?
GOT IT! thx so so much :)
\[\left( \sqrt{13x+13} \right)^{2} = \left( x+1 \right)^{2}\] \[x ^{2}+2x+1=13x+13\] \[x ^{2}-11x-12\] x=(-1,12)
champion is right
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