Question

solve using the quadratic equation.
2x^2-3x=-3

Answer 1

2x2 -3x+3=0

x_1,_2=(3+/- sqrt(9-24))/4

Answer 2

2x^2 -3x+3=0

a=2, b=-3, c=3

plug into the quadratic equation which the answer would be:

3+/- i√15
___________
4

+/- = plus or minus

Answer 3

lets move the -3 over

2x^2 - 3x + 3 = 0

you can already see that its impossible to factor since no two numbers can add up to -3 and multiply 3. Thats why you are using the quadratic in this.

The general form of this equation is ax^2 + bx + c = 0

and the quadratic formula is (-b +/- sqrt(b^2-4ac))/2a

so lets plug in

(3 + sqrt(9 - 4(2)(3))/4) and (3 - sqrt(9 - 4(2)(3))/4)

then you solve it from there to get the 2 different values of x.

Answer 4

ok, i got 3+/-sqrt(-15)/4. it says to use i for complex numbers? not sure what that means and if i need to use it here?

Answer 5

us (3+/- isqrt(15)/4

Answer 6

thank you!