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solve 9x^4-21x^2+10=0
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This is long one! :(
Set u = x^2 and then you have a quadratic equation in u, as u^2 = x^4
factors of 90 that add to -21.....
are you following what I said?
discriminant is 81, a perfect square, so it should factor.
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it does factor
but just use quad formula after a while.
ok, i got +/-sqrt 5/3 and +/- sqrt 2/3 ???
\[x= \frac{ 21 +- 9}{18}\]
(3x^2 - 2)(3x^2 - 5) = 0, yes.
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so pixie yes
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